The ratio in which the line segment joining the points whose position vectors are 2^i−4^j−7^k and −3^i+5^j−8^k is divided by the plane whose equation is ^r.(^i−2^j+3^k)=13 is
A
13:12 internally
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B
12:25 externally
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C
13:25 internally
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D
37:25 internally
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Solution
The correct option is B12:25 externally Let P be the point and it divides the line segment in the ratio λ:1. Then, −−→OP=→r=−3λ+2λ+1^i+5λ−4λ+1^j+−8λ−7λ+1^k
It satisfies →r.(^i−2^j+3^k)=13. ∴−3λ+2λ+1−25λ−4λ+1+3−8λ−7λ+1=13 ⇒−3λ+2−2(5λ−4)+3(−8λ−7)=13(λ+1) ⇒−37λ−11=13λ+13 ⇒λ=−1225