The correct option is D 2:3
Given points are (3,−4) and (−5,6)
Let the ratio be m:n
Now, the required coordinates of point on x− axis
=(−5m+3nm+n,6m−4nm+n)
As the point lies on x− axis, so y coordinate will be zero, we get
6m−4nm+n=0⇒6m−4n=0∴mn=23
Alternate method:
If coordinates of two points are (x1,y1) and (x2,y2)
x− axis divides in ratio of
mn=−y1y2
Given coordinates are y1=−4,y2=6
∴mn=23