The ratio in which X-axis divides the line segment joining $(3, 6)$ and $(12, - 3)$ is ....

3 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $2 : 1$
Given $(3, 6) (12, - 3)$

$A (3, 6) B (12, - 3)$
$x_{1} y_{1}$ $x_{2} y_{2}$

$P$ be $(x, 0)$ [As we want ratio of x-axis]

$(x, 0) P = (\frac{m_{1} x_{2} + m_{2} x_{1}}{m_{1} + m_{2}}, \frac{m_{1} y_{2} + m_{2} y_{1}}{m_{1} + m_{2}})$

$0 = \frac{m_{1} (- 3) + m_{2} (6)}{m_{1} + m_{2}}$

$- 3 m_{1} + 6 m_{2} = 0$

$6 m_{2} = 3 m_{1}$

$\frac{m_{1}}{m_{2}} = \frac{6}{3} = \frac{2}{1}$

$m_{1} : m_{2} = 2 : 1$

Suggest Corrections

Similar questions

The ratio in which the x-axis divides the segment joining A(3,6) and B(12,-3) is

(- 3, 6)

(12, - 3)

Join BYJU'S Learning Program