The ratio of 24Cr:25Cr when each of them has the greatest value possible is:
A
12:25
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B
13 : 25
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C
13 : 24
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D
1 : 2
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Solution
The correct option is D 13 : 25 Note that 2nCr is maximum if and only if r=n and 2n−1Cr is maximum if and only if r=n−1 or r=n. Hence 24Cr is maximum when r=12 and 25Cr is maximum when r=12. The ratio 24C12:25C12 is : 24C1225C12=24!12!12!25!12!13!