The correct option is A 120
Let the two digit number be 10a+b and the number formed by reversing its digits be 10b+a.
Then, 10a+b10b+a=47
⇒70a+7b=40b+4a
⇒66a=33b
⇒b=2a
When a=1,b=2; number =12
When a=2,b=4; number =24
When a=3,b=6; number =36
When a=4,b=8; number =48
When a=5,b=10; that is not a single digit (reject it)
Sum of all such numbers =12+24+36+48=120