Question

The ratio of active masses of $22$g $C{O}_2$, $3g$ $H_2$ and $7g$ $N_2$ in a gaseous mixture:-

• A. $22:3:7$
• B. $0.5:3:7$
• C. $1:3:1$
• D. $1:3:0.5$

Answer 1

The correct option is D $1:3:0.5$

Ratio of active masses of 22g $C{O}_2$, 3g $H_2$ and 7g $N_2$ in a gaseous mixture is $1:3:0.5$.

The ratio of active masses corresponds to the ratio of a number of moles.

The molar masses of $C{O}_2$, $H_2$ and $N_2$ are 44 g/mol, 2 g/mol and 7 g/mol respectively.

Hence, their number of moles are $0.5,1.5$ and $0.25$ respectively.