The ratio of amounts of $H_{2} S$ needed to precipitate all, the metal ions from 100 ml of $1 M A g N O_{3}$ and 100 ml of $1 M C u S O_{4}$ will be:

1 : 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

indefinite

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $1 : 2$
The ratio of amounts of $H_{2} S$ needed to precipitate all, the metal ions from 100 ml of 1 M $A g N O_{3}$ and 100 ml of 1M $C u S O_{4}$ will be 1 $:$ 2.
$2 A g N O_{3} + H_{2} S \to A g_{2} S ↓ + 2 H N O_{3}$
100 mL of 1 M $A g N O_{3}$ will require $\frac{1 M \times 0.1 L}{2} = 0.05$ moles of $H_{2} S$ .
$C u S O_{4} + H_{2} S \to C u S ↓ + H_{2} S O_{4}$
100 mL of 1 M $C u S O_{4}$ will require $1 M \times 0.1 L = 0.1$ moles of $H_{2} S$ .
The ratio of amounts of $H_{2} S$ needed to precipitate all, the metal ions from 100 ml of 1 M $A g N O_{3}$ and 100 ml of 1M $C u S O_{4}$ will be 1 $:$ 2.

Suggest Corrections

Similar questions

Q. The ratio of amounts of

H_{2} S

needed to precipitate all the metal ions from 100 ml of 1 M

A g N O_{3}

and 100 ml of 1 M

C u S O_{4}

will be

Q. The ratio of amounts of

H_{2} S

needed to precipitate all the metal ions from 100 ml of 1 M

A g N O_{3}

and 100 ml of 1 M

C u S O_{4}

will be :

The ratio of the molar amounts of $H_{2} S$ needed to precipitate the metal ions from $20 m L$ each of 1M $C d (N O_{3})_{2}$ and 0.5 M $C u S O_{4}$ is

Q. The ratio of the molar amounts of

H_{2} S

needed to precipitate the metal ions from 20 ml each of 1M

C d (N O_{3})_{2}

and

0.5 M C u S O_{4}

is:

Join BYJU'S Learning Program

The ratio of amounts of H2S needed to precipitate all, the metal ions from 100 ml of 1MAgNO3 and 100 ml of 1MCuSO4 will be:

The ratio of amounts of $H_{2} S$ needed to precipitate all, the metal ions from 100 ml of $1 M A g N O_{3}$ and 100 ml of $1 M C u S O_{4}$ will be: