The ratio of amplitudes of two waves having same frequency is 3:1. Find the ratio of maximum and minimum intensities.
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Solution
Given : A1A2=31 ⟹A1=3A2 Maximum intensity Imax=(A1+A2)2 Minimum intensity Imin=(A1−A2)2 Thus ratio of maximum to minimum intensity ImaxImin=(A1+A2A1−A2)2 Or ImaxImin=(3A2+A23A2−A2)2 Or ImaxImin=(42)2=(2)2=4