Question

The ratio of area of two squares, one having double its diagonal than the other, is ________.

• A. $3:2$
• B. $4:1$
• C. $3:1$
• D. $4:3$

Answer 1

Answer: (B)

$4:1$

Let diagnol of second square is double the diagnol of first square.

$\Rightarrow d_2=2d_1$

we k.n.t area of square with diagnol $d$ is $\frac{d^2}{2}$.

Area of square 2 : Area of square 1 = $\frac{d_2^2}{2}:\frac{d_1^2}{2}=d_2^2:d_1^2=(2d_1{)}^2:d_1^2=4:1$

$\therefore$ratio of areas of squares is $4:1$.