Question

The ratio of Boyle's temperature and critical temperature for a gas is:

• A. 8/27
• B. 27/8
• C. 1/2
• D. 2/1

Answer 1

The correct option is B

27/8

Boyle’s Temperature , $T_B=\frac{a}{Rb}$

Critical Temperature , $T_C=\frac{8a}{27Rb}$

Here a and b are van der Waal’s constants

R is molar gas constant

Ratio of both temperatures i.e.,$\frac{T_B}{T_C}=\frac{a}{Rb}\times \frac{27Rb}{8a}=\frac{27}{8}$