The ratio of Boyle’s temperature and critical temperature for a gas is
A
827
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B
278
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C
12
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D
21
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Solution
The correct option is B278 Boyle's temperature is given as: Tb=abR...(i) Critical temperature is given as: Tc=8a27bR...(ii) Dividing equation (i) and (ii), we get, TbTc=abR8a27bR TbTc=(abR)×(27bR8a) TbTc=278