The ratio of close packed atoms to tetrahedral holes in cubic close packing is

1 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
1 : 2

Number of tetrahedral holes are double the number of sphere.

Suggest Corrections

Similar questions

The ratio of close packed atoms to tetrahedral holes in cubic close packing is

The ratio of the number of atoms to tetrahedral holes in a unit cell with cubic close packing is:

M g O

{M g}^{2 +}

O^{2 -}

0.066

0.140 n m

{M g}^{2 +}

Join BYJU'S Learning Program