The ratio of curved surface area of two cylinders having the same height is 5:6. The ratio of their volumes will be equal to
25 : 36
Let r1 and h1be the radius and height of cylinder 1
Let r2 and h2be the radius and height of cylinder 2
Curved Surface area 1Curved surface area 2=2πr1h12πr2h2
⇒56=r1hr2h
⇒56=r1r2 (as h_1 = h_2)
Ratio of volume will be equal to
V1V2=πr21h1πr22h2
Since h_1 = h_2
V1V2=(r1r2)2=(56)2=2536=25:36