The ratio of densities of nitrogen and oxygen is 14:16. The temperature at which the speed of sound in nitrogen will be same as that in oxygen at $55^{\circ} C$ is

$35^{\circ} C$

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$48^{\circ} C$

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$65^{\circ} C$

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$14^{\circ} C$

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Solution

The correct option is D
$14^{\circ} C$

$V$ = $\sqrt{\frac{r R T}{M}} V_{1}$ = $V_{2}$ $\Rightarrow$ $\sqrt{\frac{T_{1}}{M_{1}}}$ = $\sqrt{\frac{T_{2}}{M_{2}}}$

Substituting the values, we get, T= $14^{\circ} C$

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The ratio of densities of nitrogen and oxygen is 14:16. The temperature at which the speed of sound in nitrogen will be same as that in oxygen at 55∘C is

The correct option is D 14∘C V = √rRTMV1 = V2 ⇒ √T1M1 = √T2M2 Substituting the values, we get, T=14∘C

The ratio of densities of nitrogen and oxygen is 14:16. The temperature at which the speed of sound in nitrogen will be same as that in oxygen at $55^{\circ} C$ is

The correct option is D
$14^{\circ} C$

$V$ = $\sqrt{\frac{r R T}{M}} V_{1}$ = $V_{2}$ $\Rightarrow$ $\sqrt{\frac{T_{1}}{M_{1}}}$ = $\sqrt{\frac{T_{2}}{M_{2}}}$

Substituting the values, we get, T= $14^{\circ} C$