The ratio of $E_{2} - E_{1}$ to $E_{4} - E_{3}$ for the hydrogen atom is approximately equal to

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Solution

The correct option is C 15
$E_{1} = - 13.6$ eV/atom
$E_{2} = - 3.4$ eV/atom
$E_{3} = - 1.51$ eV/atom
$E_{4} = - 0.85$ eV/atom
Hence, $E_{2} - E_{1} = - 3.4 + 13.6 = + 10.2$
$E_{4} - E_{3} = - 0.85 + 1.51 = + 0.66$
Thus $\frac{10.2}{0.66} = 15.45$

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