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Question

The ratio of e/m, i.e., specific charge for a cathode ray:

A
has the smallest value when the discharge tube is filled with H2.
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B
is constant.
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C
varies with the atomic number of gas in the discharge tube.
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D
varies with the atomic number of an element forming the cathode.
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Solution

The correct option is A is constant.
The ratio of e/m,(charge/mass) i.e., specific charge for a cathode ray is constant.
cathode rays are made of electrons and independent of medium used.
Mass of electron =me and
Charge of electron =e So e/m=e/me=1.75882008839×1011 C/kg = constant

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