The ratio of electric field at a point A and at point B due to the uniformly charged spherical conductor as shown, is

2:5

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1:3

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1:1

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Solution

The correct option is C
0

We know that net electric field inside a conductor of any shape is zero under electrostatic conditions (In fact that’s why the electrostatic condition is maintained). So electric field at A would be zero. Electric field at B however will be a finite no. i.e. $| \to E | = \frac{K Q}{R^{2}}$

(as the sphere behaves like a point charge when calculating electric field at an outside point).

The ratio will be zero.

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