The ratio of electric field due to an electric dipole on its axis and on the perpendicular bisector of dipole is

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Solution

Step 1 . At axial point of dipole
Electric field = $E = \frac{2 k p}{r^{3}}$
Step 2 , At equitorial position (perpendicular bisector)
Electric field = $E = \frac{2 k p}{r^{3}}$
Step 3 ,Finding ratio of step1 to step 2
Ratio = 2
Final answer is Ratio = 2

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The ratio of electric field due to an electric dipole on its axis and on the perpendicular bisector of dipole is

Step 1 . At axial point of dipole Electric field = E=2kpr3 Step 2 , At equitorial position (perpendicular bisector)Electric field = E=2kpr3 Step 3 ,Finding ratio of step1 to step 2Ratio = 2Final answer is Ratio = 2

Step 1 . At axial point of dipole
Electric field = $E = \frac{2 k p}{r^{3}}$
Step 2 , At equitorial position (perpendicular bisector)
Electric field = $E = \frac{2 k p}{r^{3}}$
Step 3 ,Finding ratio of step1 to step 2
Ratio = 2
Final answer is Ratio = 2