The ratio of excluded volume (b) to molar volume of a gas molecule is:

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Solution

The correct option is D 4
As we know,
$b (c o - v o l u m e) = 4 [\frac{4}{3} π r^{3}]$
$= 4$ (Volume occupied by gaseous molecule)
$b = 4$ (volume of gas molecule)
$∴ \frac{b}{V o l u m e o f g a s m o l e c u l e} = 4$

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The ratio of excluded volume (b) to molar volume of a gas molecule is:

The correct option is D 4As we know,b(co−volume)=4[43πr3] =4 (Volume occupied by gaseous molecule)b=4(volume of gas molecule)∴bVolumeofgasmolecule=4

The correct option is D 4
As we know,
$b (c o - v o l u m e) = 4 [\frac{4}{3} π r^{3}]$
$= 4$ (Volume occupied by gaseous molecule)
$b = 4$ (volume of gas molecule)
$∴ \frac{b}{V o l u m e o f g a s m o l e c u l e} = 4$