The ratio of frequencies of oscillation for two simple pendulums are 2:3, then their respective lengths are in ratio:
A
√23:1
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B
√32:1
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C
4:9
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D
9:4
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Solution
The correct option is D9:4 Frequency of oscillation of simple pendulum is f=1T ⇒f=12π√gl ⇒f∝1√l ⇒f1f2=√l2l1 ⇒l1l2=(f2f1)2=(32)2=94∵(f1:f2=2:3), ⇒l1:l2=9:4