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Application of Electrolysis

The ratio of ...

Question

The ratio of gases liberated at anode and cathode during electrolysis of C $_{3}$ H $_{7}$ COONa(aq) is 2:1.
If true enter 1, else enter 0.

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Solution

The electrolysis of aqueous concentrated solution of sodium butyrate yields n hexane.
$2 C_{3} H_{7} C O O N a + 2 H_{2} O e l e c t r o l y s i s - ------ \to C_{3} H_{7} - C_{3} H_{7} + 2 C O_{2} + 2 K O H + H_{2}$
On electrolysing the solution of sodium butyrate the mole ratio of gases formed at anode and cathode is 2:1.
$C O_{2}$ is formed at anode and $H_{2}$ is formed at cathode.

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