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Question

The ratio of heats liberated at 298K from the combustion of one kg of coke and by burning water gas obtained from kg of coke is :

Given: Enthalpies of combustion of C,CO and H2 as 393.5kJ, 285kJ, 285kJ respectively all at 298K. (Assume coke to be 100% carbon).

A
0.69:1
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B
0.96:1
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C
0.79:1
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D
0.86:1
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Solution

The correct option is A 0.69:1
The ratio of heats liberated at 298K from the combustion of one kg of coke and by burning water gas obtained from kg of coke

=enthalpy of combustion of Centhalpy of combustion of CO+enthalpy of combustion of hydrogen= 393.5285+285=0.69:1

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