The ratio of $K_{p} / K_{c}$ for the reaction: $C O (g) + 1 / 2 / O_{2} (g) ⇌ C O_{2} (g)$ is :

1

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R T

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(R T)^{1 / 2}

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(R T)^{- 1 / 2}

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Solution

The correct option is D $(R T)^{- 1 / 2}$
$K_{P} = K_{C} (R T)^{Δ n}$ $Δ n = 1 - \frac{1}{2} - 1 = - \frac{1}{2}$
Given $C O + \frac{1}{2} O_{2} ⇌ {C O_{2}}_{(g)}$
$\Rightarrow \frac{K_{P}}{K_{C}} = (R T)^{- 1 / 2}$ .

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