The ratio of $(E_{2} - E_{1})$ to $(E_{4} - E_{3})$ for the hydrogen atom is approximately equal to:

10

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15

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17

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12

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Solution

The correct option is C $15$
In hydrogen atom formula for energy is $E = - 13.6 \frac{z^{2}}{n^{2}}$ , Where z = Atomic number, n = Principle quantum number.
Thus, $E_{4} = \frac{- 1}{16}$ , $E_{3} = \frac{- 1}{9}$ , $E_{1} = - 1$ , $E_{2} = \frac{- 1}{4}$
Using above formula $\frac{E_{2} - E_{1}}{E_{4} - E_{3}}$ = $15.42$
so, answer is B

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