Question

The ratio of magnetic dipole moment to angular momentum in a hydrogen like atom is :

• A. $\frac{e}{m}$
• B. $\frac{e}{2m}$
• C. $\frac{e}{3m}$
• D. $\frac{2e}{m}$

Answer 1

The correct option is B $\frac{e}{2m}$

$\mu =I.A$ $=qf.A$ $=\frac{qw}{2\pi }.\pi R^2$
$=\frac{2w{R}^2}{2}$$=\frac{ew{R}^2}{2}$
$L=mvR$
$=m{R}^{2}w$
$\frac{\mu }{L}=\frac{e}{2m}$