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Question

The ratio of magnetic dipole moment to that of the angular momentum of an electron of mass m kg and charge e C. In Bohr's orbit of the hydrogen atom is-

A
em
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B
2em
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C
e2m
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D
(em)2
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Solution

The correct option is C e2m
The magnetic dipole moment of an electron is,

μB=iA=(ev2πr)(πr2)=12evr ......(1)

The angular momentum of the electron is,

L=mvr vr=Lm ........(2)


From (1) & (2) we get,

μB=12eLm

μBL=e2m

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (C) is the correct answer.


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