MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Current Loop Is a Magnet?

The ratio of ...

Question

The ratio of magnetic fields due to a smaller bar magnet in the end on position to broad side on position is

A

1 / 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

1 / 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $2$
End on position corresponds to axial line and Broadside on position corresponds to equatorial line.
Therefore, $B_{1} / B_{2} = 2$ .

Suggest Corrections

thumbs-up

0

Similar questions

Q. Derive an expression for the intensity of magnetic field on broad side on position due to a bar magnet.

The ratio of magnetic potential due to magnetic dipole at the end to that at the broad side on a position for the same distance from it is :

Q. Due to a small magnet, intensity at a distance x in the end on position is

9

gauss. What will be the intensity at a distance

\frac{x}{2}

on broad side on position.

Q. Ratio of magnetic intensities for an axial point and a point on broad side-on position at equal distance d from the centre of magnet will be or The magnetic field at a distance d from a short bar magnet in longitudinal and transverse positions are in the ratio

Q. A bar magnet having centre O has a length of 4 cm. Point

P_{1}

is in the broad side-on and

P_{2}

is in the end side-on position with

O P_{1} = O P_{2} = 10

metres. The ratio of magnetic intensities H at

P_{1}

P_{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Torque on a Magnetic Dipole

PHYSICS

Watch in App

explore_more_icon

Explore more

Current Loop Is a Magnet?

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon