The ratio of magnetic force $(F_{m})$ and electric force $(F_{e})$ acting on a moving charge is

{(\frac{V}{C})}^{2}

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{(\frac{C}{V})}^{2}

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\frac{V}{C}

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\frac{C}{V}

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Solution

The correct option is C $\frac{V}{C}$
$F_{e l e c t r i c} = q E$
$F_{m a g} = q v B$
$\frac{F_{m a g}}{F_{e l e c t r i c}} = \frac{v B}{E} = v \frac{B}{E} = \frac{v}{c}$

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