The ratio of mass of nitrogen and oxygen in nitric oxide is:

7 : 16

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1 : 8

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7 : 8

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7 : 15

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Solution

The correct option is B $7 : 8$
The formula of nitric oxide is NO.

Mass of nitrogen in NO is 14 g.

Mass of oxygen is 16 g.

Therefore, ratio is 14:16 = 7:8.

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Similar questions

Q. An oxide of nitrogen is found to contain nitrogen and oxygen combined together in the ratio

7 : 16

by mass. Derive formula of oxide and name it.

What is the chemical formula of a compound made of Nitrogen and Oxygen with the mass ratio of 7:8?

Q. At

27^{o} C

, the ratio of the kinetic energies of nitrogen and oxygen whose weights ratio is

7 : 8

is:

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Q. If normal at

P (2, \frac{3 \sqrt{3}}{2})

meets the major axis of the ellipse

\frac{x^{2}}{16} + \frac{y^{2}}{9} = 1

Q

and

S, S^{'}

are foci of given ellipse along positive and negative directions of axes, then the ratio

S Q : S^{'} Q

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The ratio of mass of nitrogen and oxygen in nitric oxide is:

The correct option is B 7:8The formula of nitric oxide is NO. Mass of nitrogen in NO is 14 g. Mass of oxygen is 16 g. Therefore, ratio is 14:16 = 7:8.

The correct option is B $7 : 8$
The formula of nitric oxide is NO.

Mass of nitrogen in NO is 14 g.

Mass of oxygen is 16 g.

Therefore, ratio is 14:16 = 7:8.