CameraIcon

SearchIcon

MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Vector Component

The ratio of ...

Question

The ratio of maximum and minimum magnitudes of the resultant of two vectors $¯ A$ and $¯ B$ is 3:2. The relation between A and B is:

A

A = 5 B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

5 A = B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

A = 3 B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

A = 4 B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $A = 5 B$
$(\to A + \to B)_{m a x} = A + B$ .
$(\to A + \to B)_{m i n} = A - B$
Therefore, $\frac{A + B}{A - B} = \frac{3}{2}$
$\Rightarrow 2 A + 2 B = 3 A - 3 B$
$\Rightarrow A = 5 B$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The ratio of maximum and minimum magnitudes of the resultant of two vectors

\to a

\to b

is 3 : 1. Now ,

| \to a |

Q. Given position vectors

¯ a, ¯ b, ¯ c

of points A, B, C for a triangle. The centroid can be given by

If \to A and \to B are two unit vectors such that 3 \to A + 4 \to B and 5 \to A - 3 \to B are perpendicular, then the angle between \to A and \to B is

¯ a, ¯ b, ¯ c

be vectors equal magnitude such that the angle between

¯ a

¯ b

α

¯ b

¯ c

β

¯ c

¯ a

γ

. Then the minimum value of

c o s α + c o s β + c o s γ

\to a

\to b

be two unit vectors, maximum value of

\frac{{∣ ∣ ¯ a + ¯ b ∣ ∣}^{2} - {∣ ∣ ¯ a - ¯ b ∣ ∣}^{2}}{{∣ ∣ ¯ a + ¯ b ∣ ∣}^{2} + {∣ ∣ ¯ a - ¯ b ∣ ∣}^{2}}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Vector Components

PHYSICS

Watch in App

explore_more_icon

Explore more

Vector Component

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon