The ratio of mean value over half cycle to r.m.s value of A.C. is

2 : π

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2 \sqrt{2} : π

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\sqrt{2} : π

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\sqrt{2} : 1

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Solution

The correct option is B $2 \sqrt{2} : π$
We know that $I_{m a x} = I_{0} / \sqrt{2}$ and $I_{m} = 2 I_{0} / π$
$∴$ $\frac{I_{m}}{I_{r m s}} = \frac{2 \sqrt{2}}{π}$

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