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Question

The ratio of nth term of two AP's is (14n−6):(8n+23), then the ratio of their sum of first m terms is

A
4m+47m+24
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B
7m14m+24
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C
7m+14m+27
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D
28m2016m+15
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Solution

The correct option is C 7m+14m+27
TnTn=a1+(n1)d1a1+(n1)d1=14n68n+23
comparing coff.of n & constant terms
d1=14,a1d1=6a1=8
d1=8,a1d1=23a1=31
Ratio of sum of 1st m terms =m/2(2a1+(m1)d1)m/2(2a1+(m1)d1)
=2a1+(m1)d12a1+(m1)d1=16+(m1)1462+(m1)8
=2+14m54+8m=1+7m4m+27(C)

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