The ratio of neutrons in $O^{16}$ and $O^{18}$ is

8 : 10

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4 : 5

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9 : 8

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1 : 1

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Solution

The correct options are
A $8 : 10$
C $4 : 5$
The ratio of neutrons in $O^{16}$ and $O^{18}$ is $4 : 5 or 8 : 10$
Number of neutrons in $O^{16} = 16 - 8 = 8$
Number of neutrons in $O^{18} = 18 - 8 = 10$

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Similar questions

O^{16} a n d O^{18}

O^{16}

O^{18}

_{1} H^{1}

_{1} H^{2}

_{1} H^{3}

_{8} O^{16}

_{8} O^{17}

_{8} O^{18}

Out of $O^{16}$ and $O^{18}$ isotopes, which has more number of neutrons?

If A:B = $\frac{1}{2} : \frac{3}{8}$ , B:C = $\frac{1}{3} : \frac{5}{9}$ and C:D = $\frac{5}{6} : \frac{3}{4}$ , then the ratio A:B:C:D is

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