The ratio of nuclear magneton and Bohr magneton is

m_{e} / m_{p}

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m_{p} / m_{e}

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m_{e} m_{p}

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2 m_{p} / m_{e z}

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Solution

The correct option is B $m_{e} / m_{p}$
Nuclear magneton is given by: $μ_{N} = \frac{e ¯ h}{2 m_{p}}$
Bohr magneton is given by: $μ_{B} = \frac{e ¯ h}{2 m_{e}}$
where, variables have their usual meanings
$\frac{μ_{N}}{μ_{B}} = \frac{\frac{e ¯ h}{2 m_{p}}}{\frac{e ¯ h}{2 m_{e}}}$
$\frac{μ_{N}}{μ_{B}} = \frac{m_{e}}{m_{p}}$

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Similar questions

The value of Bohr magneton $(μ_{B})$ is :

m_{e}

m_{p}

m_{p}

=

1836

m_{e}

\frac{λ_{electron}}{λ_{proton}}

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