The ratio of number of turns of primary coil to secondary coil in a transformer is 2:3. If a source of 6V ac is connected across the primary coil, then e.m.f. across the secondary coil (in volts) will be
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Solution
Given : number of turns in primary coil, Np=2N,
number of turns in secondary coil Ns=3N and
supply voltage on primary coil, ϵp=6V.
Now, ϵPϵS=NPNS,ϵS=ϵP×NSNP=6×3N2N=9V.