The ratio of $O$ to $H$ atoms in ${({N H}_{4})}_{2} {S O}_{4}$ is:

1 : 1

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2 : 1

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1 : 2

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4 : 1

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Solution

The correct option is C $1 : 2$
In the compound $(N H_{4})_{2} {S O}_{4}$
Number of Oxygen(O) atoms $= 4$
Number of Hydrogen(H) atoms $= 8$
Ratio of O to H is O:H $= 4 : 8 := 1 : 2$

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The ratio of O to H atoms in (NH4)2SO4 is:

The correct option is C 1:2In the compound (NH4)2SO4Number of Oxygen(O) atoms =4Number of Hydrogen(H) atoms=8Ratio of O to H is O:H=4:8:=1:2

The ratio of $O$ to $H$ atoms in ${({N H}_{4})}_{2} {S O}_{4}$ is:

The correct option is C $1 : 2$
In the compound $(N H_{4})_{2} {S O}_{4}$
Number of Oxygen(O) atoms $= 4$
Number of Hydrogen(H) atoms $= 8$
Ratio of O to H is O:H $= 4 : 8 := 1 : 2$