The ratio of positive ions to negative ions in calcium chloride is

1:2

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2:1

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1:1

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2:2

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Solution

The correct option is A
1:2

Molecular formula for calcium chloride = ${CaCl}_{2}$
Positive ion = ${Ca}^{+ 2}$
Negative ion = ${Cl}^{- 1}$
For balancing the charges, we have one calcium atom and two chlorine atom.
Required ratio = 1:2

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M g C l_{2}

Question 26
Calcium chloride when dissolved in water dissociates into its ions according to the following equation.

$C a C l_{2} (a q) \to C a^{2 +} (a q) + 2 C l^{-} (a q)$

Calculate the number of ions obtained from $C a C l_{2}$ when 222 g of it is dissolved in water.

{C a}^{2 +}

C a C l_{2 (a q)} \to C a_{a q}^{2 +} + 2 C l_{a q}^{-}

C a C l_{2}

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