Question

The ratio of pure and hybrid orbitals of valence shell in $H_{2}C=CH-CH=C{H}_2$ is:

• A. $7:12$
• B. $14:13$
• C. $6:5$
• D. $5:6$

Answer 1

The correct option is D $5:6$

Every double bonded carbon has $3$ $s{p}^2$ orbitals and one pure p orbital. And every hydrogen has one pure s orbital, so the number of hybrid orbitals are $4\times 3=12$, and pure orbitals are $1\times 4+6\times 1=10$.
So, their ratio is $10:12$ or $5:6$.