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Question

The ratio of radii of first Bohr orbits of H, He+ and Li2+ is:

A
6:2:3
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B
6:3:2
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C
2:6:3
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D
3:2:6
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Solution

The correct option is B 6:3:2
Bohr's radius for nth orbit, rn=0.529[n2Z]A
where n=Energy level, Z=Atomic number

For H atom: n=1, Z=1
rH=0.529[121]A

For He+ ion: n=1, Z=2
rHe+=0.529[122]A

For Li2+ ion: n=1, Z=3
rLi2+=0.529[123]A

Upon taking ratio, rH:rHe+:rLi2+=1:12:13

On simplifying, we get the ratio as:
6:62:63 i.e., 6:3:2


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