CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The ratio of radii of nuclei 13Al27 and 52XP is 3:5. The number of neutrons in the nuclei of X will be

Open in App
Solution

rA1/3r1r2=(A1A2)1/3Substituting the values35=(27P)1/327125=27PP=125
Number of neutrons in atom
X=P52
=12552
=73

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon