Question

The ratio of radii of nuclei ${}_{13}^{27}$ Al and ${}_{52}^{125}$ Te is approximately

• A. 6 : 10
• B. 13 : 52
• C. 40 : 177
• D. 14 : 7

Answer 1

The correct option is A 6 : 10

By using $r\propto A^{\frac{1}{3}}\Rightarrow \frac{r_1}{r_2}={\left(\frac{A_1}{A_2}\right)}^{\frac{1}{3}}={\left(\frac{27}{125}\right)}^{\frac{1}{3}}=\frac{3}{5}=\frac{6}{10}$