The ratio of radii of two wires of the same material is 2:1. If these wires are stretched by equal forces, then the ratio of stresses produced in them will be
A
4:1
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B
3:1
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C
1:4
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D
1:3
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Solution
The correct option is C1:4 Stress=ForceArea=Fπr2 Given F is constant. ∴StressS∝1r2 i.e (S1S2)=(r2r1)2 Given r1r2=21 ∴S1S2=14