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Kinetic Theory of Gases

The ratio of ...

Question

The ratio of rate of diffusion of He (at 4 $a t m$ ) and $C H_{4}$ (1 $a t m$ ) through same pin hole at constant temperature is .....

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Solution

as we know,
rate of diffusion of a gas is inversely proportional to square root of molar mass so
$r_{1} / r_{2} = P_{1} / P_{2} \sqrt{M_{2} / M_{1}}$
$r_{H e} / r_{C H_{4}} = 4 / 1 * \sqrt{16 / 4} = 8$

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