The ratio of rate of diffusion of helium and methane under identical conditions of pressure and temperature will be :

4

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2

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Solution

The correct option is A $2$
Using Graham's law of diffusion,

$\frac{r_{C H_{4}}}{r_{H e}} = \sqrt{\frac{M_{H e}}{M_{C H_{4}}}} = \sqrt{\frac{4}{16}} = \frac{1}{2}$

$r_{H e} = 2 r_{C H_{4}}$

Hence the correct option is B.

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The ratio of rate of diffusion of helium and methane under identical conditions of pressure and temperature will be :

The correct option is A 2Using Graham's law of diffusion,rCH4rHe=√MHeMCH4=√416=12rHe=2rCH4Hence the correct option is B.

The correct option is A $2$
Using Graham's law of diffusion,

$\frac{r_{C H_{4}}}{r_{H e}} = \sqrt{\frac{M_{H e}}{M_{C H_{4}}}} = \sqrt{\frac{4}{16}} = \frac{1}{2}$

$r_{H e} = 2 r_{C H_{4}}$

Hence the correct option is B.