Question

The ratio of resolving power of an optical microscope for two wavelengths ${\lambda }_1=4000\AA$ and ${\lambda }_2=6000\AA$ is

• A. 9:4
• B. 3:2
• C. 16:81
• D. 8:27

Answer 1

The correct option is B 3:2

As we know,
Resolving power $\propto \frac{1}{\lambda }$
$\frac{R{P}_1}{R{P}_2}=\frac{{\lambda }_2}{{\lambda }_1}$
$\frac{R{P}_1}{R{P}_2}=\frac{6000\AA }{4000\AA }\Rightarrow \frac{3}{2}$