The ratio of root mean square velocity to average velocity of gas molecules at a particular temperature is

1.086 : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 : 1.086

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 1.086

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.086 : 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
1.086 : 1

$V_{r m s} = \sqrt{\frac{3 R T}{M}}, V_{a v} = \sqrt{\frac{8 R T}{π M}}; \frac{V_{r m s}}{V_{a v}} = \sqrt{\frac{3 π}{8}} = \sqrt{\frac{66}{56}} \Rightarrow \frac{1.086}{1}$

Suggest Corrections

Similar questions

1

800

600

C u {S O}_{4} .5 H_{2} O

C u {S O}_{4} .3 H_{2} O

C u {S O}_{4} .5 H_{2} O (s) ⇌ C u {S O}_{4} .3 H_{2} O (s) + 2 H_{2} O (v)

K_{P} = 1.086 \times 10^{- 4} {a t m}^{2}

{C u S O}_{4} \cdot 5 H_{2} O (s) ⇌ {C u S O}_{4} \cdot {3 H}_{2} O (s) + {2 H}_{2} O (l) K_{p} = 1.086 \times 10^{- 4} {a t m}^{2} a t 25^{o} C

{C u S O}_{4} \cdot {5 H}_{2} O

H_{2} O

Join BYJU'S Learning Program