The ratio of saturated unit weight to dry unit weight of a soil is 1.25. If the specific gravity of solids $(G_{s})$ is 2.65, the void ratio of the soil is

0.625

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0.663

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0.944

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1.325

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Solution

The correct option is B 0.663
Given,

$\frac{γ_{s a t}}{γ_{d r y}} = 1.25$

and $G_{s} = 2.65$

$\frac{(\frac{G_{s} + S e}{(1 + e)}) γ_{w}}{\frac{G_{s} γ_{w}}{1 + e}} = 1.25$

$\frac{G_{s} + e}{G_{s}} = 1.25$

(for saturated soil S = 1)

$\frac{2.65 + e}{2.65} = 1.25$

$\Rightarrow e = 0.663$

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The ratio of saturated unit weight to dry unit weight of a soil is 1.25. If the specific gravity of solids (Gs) is 2.65, the void ratio of the soil is

The correct option is B 0.663Given, γsatγdry=1.25 and Gs=2.65 (Gs+Se(1+e))γwGsγw1+e=1.25 Gs+eGs=1.25 (for saturated soil S = 1) 2.65+e2.65=1.25 ⇒e=0.663

The ratio of saturated unit weight to dry unit weight of a soil is 1.25. If the specific gravity of solids $(G_{s})$ is 2.65, the void ratio of the soil is

The correct option is B 0.663
Given,

$\frac{γ_{s a t}}{γ_{d r y}} = 1.25$

and $G_{s} = 2.65$

$\frac{(\frac{G_{s} + S e}{(1 + e)}) γ_{w}}{\frac{G_{s} γ_{w}}{1 + e}} = 1.25$

$\frac{G_{s} + e}{G_{s}} = 1.25$

(for saturated soil S = 1)

$\frac{2.65 + e}{2.65} = 1.25$

$\Rightarrow e = 0.663$