Question

The ratio of slit widths in Young's double slit experiment is $4:9$. The ratio of maximum and minimum intensities will be

• A. $169:25$
• B. $81:16$
• C. $13:5$
• D. $25:1$

Answer 1

The correct option is D $25:1$

The intensity ratio will be same as slit width ratio

$I_1:I_2=4:9$

$\frac{I_{max}}{I_{min}}=(\frac{\sqrt{I_2}+\sqrt{I_1}}{\sqrt{I_2}-\sqrt{I_1}}{)}^2$ = $(\frac{3+2}{3-2}{)}^2$ = 25:1

Answer. D) 25:1