The ratio of $s p^{3}$ and $s p^{2}$ hybridized atoms in the anionic part of borax is:
(If answer is $12 : 4$ then represent as $0124$ )

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Solution

Borax contains boron in both planar $- (B O_{3}) -$ and tetrahedral $- (B O_{4}) -$ units. It contains five $B - O - B$ linkages. As can be seen from the above structure of borax, it contains $11 \to s p^{3}$ and $2 \to s p^{2}$ . Hence, $11 : 2$ .

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