Question

The ratio of specific charges (e/m) of a proton and an $\alpha$-particle is:

• A. 2
• B. 3
• C. 4
• D. 5

Answer 1

The correct option is A 2

We need to find the ratio of $\frac{\frac{e_p}{m_p}}{\frac{e_{\alpha }}{m_{\alpha }}}$

$m_{\alpha }$$=$$4$$m_p$
$e_{\alpha }$$=$$2$$e_p$

Substituting these values, we get:
$\frac{\frac{e_p}{m_p}}{\frac{2e_p}{4m_p}}$$=$$\frac{2}{1}$.